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256.25=x^2
We move all terms to the left:
256.25-(x^2)=0
We add all the numbers together, and all the variables
-1x^2+256.25=0
a = -1; b = 0; c = +256.25;
Δ = b2-4ac
Δ = 02-4·(-1)·256.25
Δ = 1025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1025}=\sqrt{25*41}=\sqrt{25}*\sqrt{41}=5\sqrt{41}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-5\sqrt{41}}{2*-1}=\frac{0-5\sqrt{41}}{-2} =-\frac{5\sqrt{41}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+5\sqrt{41}}{2*-1}=\frac{0+5\sqrt{41}}{-2} =\frac{5\sqrt{41}}{-2} $
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